Question
Find the area enclosed by the given figure $ABCDEF$ as per dimensions given herewith.
✓
Answer
In the figure, $ABCF$ is $0$ square and $CDEF$ is a trapezium,
Now area of square $ABCF$,
$= (side)^2= (20)^2= 400cm^2$
Area of trap. $CDEF$
$=\frac{1}{2}(\text{ED}+\text{FC})\times\text{height}$
$=\frac{1}{2}(6+20)\times8=\frac{1}{2}\times26\times8\text{cm}^2$
$=104\text{cm}^2$
$\therefore$ Total area of the figure $ABCDEF$
$= 400 + 104 = 504cm^2$
Now area of square $ABCF$,
$= (side)^2= (20)^2= 400cm^2$
Area of trap. $CDEF$
$=\frac{1}{2}(\text{ED}+\text{FC})\times\text{height}$
$=\frac{1}{2}(6+20)\times8=\frac{1}{2}\times26\times8\text{cm}^2$
$=104\text{cm}^2$
$\therefore$ Total area of the figure $ABCDEF$
$= 400 + 104 = 504cm^2$
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