Question
Find the area enclosed by the given figure ABCDEF as per dimensions given herewith.
✓
Answer
In the figure, $A B C F$ is 0 square and $C D E F$ is a trapezium,
Now area of square $A B C F$,
$=(\text { side })^2=(20)^2=400 cm^2$
Area of trap. CDEF
$=\frac{1}{2}(\text { ED }+ \text { FC }) \times \text { height } \\
=\frac{1}{2}(6+20) \times 8=\frac{1}{2} \times 26 \times 8 cm^2 \\
=104 cm^2$
$\therefore$ Total area of the figure $A B C D E F$
$=400+104=504 cm^2$
Now area of square $A B C F$,
$=(\text { side })^2=(20)^2=400 cm^2$
Area of trap. CDEF
$=\frac{1}{2}(\text { ED }+ \text { FC }) \times \text { height } \\
=\frac{1}{2}(6+20) \times 8=\frac{1}{2} \times 26 \times 8 cm^2 \\
=104 cm^2$
$\therefore$ Total area of the figure $A B C D E F$
$=400+104=504 cm^2$
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