Question
Find the area in square centimeters of a triangle whose base and altitude are as under: Base $= 18\ cm,$ altitude $= 3.5\ cm$
✓
Answer
We know that the area of a triangle $=\frac{1}{2}\text{(Base}\times\text{Height)}$
Here, base $= 18\ cm$ and height $= 3.5\ cm$
Area of the triangle $=\frac{1}{2}\times18\times3.5$ $=31.5\text{cm}^2$
Here, base $= 18\ cm$ and height $= 3.5\ cm$
Area of the triangle $=\frac{1}{2}\times18\times3.5$ $=31.5\text{cm}^2$
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