Question
Find the area of a rectangular field in hectares whose sides are: $75m$ $5dm$ and $120m$
✓
Answer
We have,
Length of the rectangular field $=75 \mathrm{~m} ~5 \mathrm{dm}=(75+0.5) \mathrm{m}$
$=75.5 \mathrm{~m} \text { [Since } 1 \mathrm{dm}=10 \mathrm{~cm}=0.1 \mathrm{~m}]$
Breadth of the rectangular field $=120 \mathrm{~m}$
Therefore, Area of the rectangular field $=$ Length $\times$ Breadth
$=75.5 \mathrm{~m} \times 120 \mathrm{~m}=9060 \mathrm{~m}^2$
$=0.906$ hectares [Since $10000 \mathrm{~m}^2=1$ hectare]
Length of the rectangular field $=75 \mathrm{~m} ~5 \mathrm{dm}=(75+0.5) \mathrm{m}$
$=75.5 \mathrm{~m} \text { [Since } 1 \mathrm{dm}=10 \mathrm{~cm}=0.1 \mathrm{~m}]$
Breadth of the rectangular field $=120 \mathrm{~m}$
Therefore, Area of the rectangular field $=$ Length $\times$ Breadth
$=75.5 \mathrm{~m} \times 120 \mathrm{~m}=9060 \mathrm{~m}^2$
$=0.906$ hectares [Since $10000 \mathrm{~m}^2=1$ hectare]
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