Question
Find the area of the circle $x^2+y^2=9$, using integration.
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(p ˄ ∼q) ˅ (∼p ˄ q) ≡ (p ˅ q) ˄ ∼(p ˄ q)
$\left( x +2 y ^2\right) \frac{d y}{d x}= y$, when $x =2, y =1$

$x^p y^4=(x+y)^{p+4}, p \in N$
$\frac{(x+1)^2}{(x+2)^3(x+3)^4}$
