Question
Find the arithmetic mean of each of the following frequency distributions using step-deviation method:
Class
$500-520$
$520-540$
$540-560$
$560-580$
$580-600$
$600-620$
Frequency
$14$
$9$
$5$
$4$
$3$
$5$

Answer

Age
Frequency $f_i$
Mid-value $x_i$
$\text{u}_\text{i}=\frac{\text{x}_\text{i}-\text{550}}{\text{20}}$
$(f_i× u_i)$
$500-520$
$14$ $510$ $-2$ $-27$
$520-540$
$9$
$530$ $-1$ $-9$
$540-560$
$5$
$550 = A$ $0$ $0$
$560-580$
$4$ $570$ $1$ $4$
$580-600$ $3$ $590$ $2$ $6$
$600-620$
$5$
$610$
$3$
$15$
 
$\sum\text{f}_\text{i}=40$
 
 
$\sum\text{f}_\text{i}\text{u}_\text{i}=-12$
Thus, $\text{A}=550,\ \text{h}=20$ and $\sum\text{f}_\text{i}=40,\ \sum\text{f}_\text{i}\text{u}_\text{i}=-12$
$\therefore$ Mean $\bar{\text{x}}=\text{A}+\Big[\text{h}\times\frac{\sum\text{(f}_\text{i}\times\text{u}_\text{i})}{\sum\text{f}_\text{i}}\Big]$
$550+\Big(\frac{-12}{40}\Big)$
$=500-6=544$

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