Question
Find the arithmetic mean of each of the following frequency distributions using step-deviation method:
Age (in years) $18-24$ $24-30$ $30-36$ $36-42$ $42-48$ $48-54$
Number of workers $6$ $8$ $12$ $8$ $4$ $2$

Answer

Class interval
Frequency $f_i$
Mid-value $x_i$
$\text{u}_\text{i}=\frac{\text{x}_\text{i}-\text{A}}{\text{h}}=\frac{\text{x}_\text{i}-203.5}{1}$
$f_i× u_i$
$18-24$
$6$ $21$ $-3$ $-18$
$24-30$
$8$
$27$ $-2$ $-16$
$30-36$
$12$
$33$ $-1$ $-12$
$36-42$
$8$ $39 =A$ $0$ $0$
$42-48$
$4$ $45$ $1$ $4$
$48-54$
$2$
$51$
$2$
$4$
 
$\sum\text{f}_\text{i}=40$
 
 
$\sum\text{f}_\text{i}\text{u}_\text{i}=-38$
Thus, $\text{A}=39,\ \text{h}=6,\ \sum\text{f}_\text{i}=40$ and $\sum\text{f}_\text{i}\text{u}_\text{i}=-38$
Mean $=\text{A}+\Big\{\text{h}\times\frac{\sum\text{f}_\text{i}\text{u}_\text{i}}{\sum\text{f}_\text{i}}\Big\}$
$=39+\Big\{16\times\frac{-38}{40}\Big\}$
$=39-5.7$
$=33.3$

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