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Factorization — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSFactorization2 Marks
Question
Find the common factors of the given term: $6abc, 24ab^2, 12a^2b$
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Answer

6abc $= 2 × 3 × a × b × c$
$24ab^2 = 2 × 2 × 2 × 3 × a × b × b$
$12a^2b = 2 × 2 × 3 × a × a × b$
Common prime factors are $2, 3, a$ and $b$
$\therefore H.C.F. = 2 \times 3 \times a \times b$
$= 6ab$

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