Question
Find the continues products:
$(3 x-2 y)(3 x+2 y)\left(9 x^2+4 y^2\right)$

Answer

$(3 x-2 y)(3 x+2 y)\left(9 x^2+4 y^2\right)$
$=\left((3 x)^2-(2 y)^2\right)\left(9 x^2+4 y^2\right)$
$=\left(9 x^2-4 y^2\right)\left(9 x^2+4 y^2\right)$
$=\left(9 x^2\right)^2-\left(4 y^2\right)^2$
$=81 x^4-16 y^4$

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