Question
Find the continues products:
$ (x+1)(x-1)\left(x^2+1\right) $
$ (x+1)(x-1)\left(x^2+1\right) $
✓
Answer
$ (x+1)(x-1)\left(x^2+1\right) $
$ \left.=\left\{(x)^2-(1)^2\right\} x^2+1\right\} $
$ =\left(x^2-1\right)\left(x^2+1\right) $
$ =\left(x^2\right)^2-(1)^2 $
$ =\left(x^4\right)-1 $
$ \left.=\left\{(x)^2-(1)^2\right\} x^2+1\right\} $
$ =\left(x^2-1\right)\left(x^2+1\right) $
$ =\left(x^2\right)^2-(1)^2 $
$ =\left(x^4\right)-1 $
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