Question
Find the continues products:
$(x+1)(x-1)\left(x^2+1\right)$
$(x+1)(x-1)\left(x^2+1\right)$
✓
Answer
$(x+1)(x-1)\left(x^2+1\right)$
$=\left\{(x)^2-(1)^2\right\}\left\{x^2+1\right\}$
$=\left(x^2-1\right)\left(x^2+1\right)$
$=\left(x^2\right)^2-(1)^2$
$=\left(x^4\right)-1$
$=\left\{(x)^2-(1)^2\right\}\left\{x^2+1\right\}$
$=\left(x^2-1\right)\left(x^2+1\right)$
$=\left(x^2\right)^2-(1)^2$
$=\left(x^4\right)-1$
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