Question
Find the continues products:
$ (x-3)(x+3)\left(x^2+9\right) $
$ (x-3)(x+3)\left(x^2+9\right) $
✓
Answer
$ (x-3)(x+3)\left(x^2+9\right) $
$ =\left\{(x)^2-(3)^2\right\}\left(x^2+9\right) $
$ =\left(x^2-9\right)\left(x^2+9\right)$
$ =\left(x^2\right)^2-(9)^2 $
$ =x^4-81 $
$ =\left\{(x)^2-(3)^2\right\}\left(x^2+9\right) $
$ =\left(x^2-9\right)\left(x^2+9\right)$
$ =\left(x^2\right)^2-(9)^2 $
$ =x^4-81 $
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