Question
Find the cube of: $0.3$
✓
Answer
We have: $0.3=\frac{3}{10}$
Also, $\Big(\frac{\text{m}}{\text{n}}\Big)^3=\frac{\text{m}^3}{\text{n}^3}$
$\therefore\Big(\frac{3}{10}\Big)^3$
$=\frac{3^3}{10^3}$
$=\frac{3\times3\times3}{10\times10\times10}$
$-0.027$
Also, $\Big(\frac{\text{m}}{\text{n}}\Big)^3=\frac{\text{m}^3}{\text{n}^3}$
$\therefore\Big(\frac{3}{10}\Big)^3$
$=\frac{3^3}{10^3}$
$=\frac{3\times3\times3}{10\times10\times10}$
$-0.027$
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