Question
Find the cube of: $\frac{12}{7}$
✓
Answer
$\because\Big(\frac{\text{m}}{\text{n}}\Big)^3=\frac{\text{m}^3}{\text{n}^3}$ $\therefore\Big(\frac{12}{7}\Big)^3$ $=\frac{12^3}{7^3}$ $=\frac{12\times12\times12}{7\times7\times7}$ $=\frac{1728}{343}$
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