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Expansions — MATHEMATICS STD 9 — Question

ICSE BoardEnglish MediumSTD 9MATHEMATICSExpansions2 Marks
Question
Find the cube of$: 4 p-\frac{1}{p}$
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Answer

$\left(4 p-\frac{1}{p}\right)^3 $
$=(4 p)^3-\left(\frac{1}{p}\right)^3-3(4 p)\left(\frac{1}{p}\right)\left(4 p-\frac{1}{p}\right) $
$ =64 p^3-\frac{1}{p^3}-48 p+\frac{12}{p}$

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