Question
Find the cube of:
$\frac{7}{9}$

Answer

$\because\Big(\frac{\text{m}}{\text{n}}\Big)^3=\frac{\text{m}^3}{\text{n}^3}$
$\therefore\Big(\frac{7}{9}\Big)^3 = \frac{7^3}{9^3} =\frac{7\times7\times7}{9\times9\times9}=\frac{343}{729}$

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