Question
Find the cube of:
$-\frac{8}{11}$

Answer

$\because\Big(\frac{\text{m}}{\text{n}}\Big)^3=\frac{\text{m}^3}{\text{n}^3}$
$\therefore\Big(-\frac{8}{11}\Big)^3= \Big(\frac{8^3}{11^3}\Big)$
$ =\Big(\frac{8\times8\times8}{11\times11\times11}\Big)=\frac{512}{131}$

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