Question
Find the cubes of the following number by column method:
$56$
$56$
|
Column I
|
Column II
|
Column III
|
Column IV
|
| $a ^3$ | $3 \times a ^2 \times b$ | $3 \times a ^{-1} b^2$ | $B^3$ |
| $5^3=125$ | $3 \times a ^2 \times b =3 \times 5^2 \times 6=450$ | $3 \times a ^2 \times b ^2=3 \times 5 \times 6^2=540$ | $6^3=216$ |
|
$+50$
|
+56
|
$+21$
|
$216$
|
|
$175$
|
506
|
$561$
|
|
|
$175$
|
6$
|
$1$
|
$6$
|
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(x – 2y + 3)² + (x + 2y – 3)²