Question
Find the derivative of function $3 \cot x + 5\ cosec\ x$

Answer

Here $f (x) = 3 \cot x + 5\ cosec\ x$
$\therefore \;{\text{f'}}(x) = \frac{d}{{dx}}[3\cot x + 5\ {\text{cosec }}\ x]$
$= 3\frac{d}{{dx}}(\cot x) + 5\frac{d}{{dx}}(cosec\ x)$
$= - 3\ cosec^2\ x - 5\ cosec\ x \cot x$

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