Question
Find the derivative of function $\sin x \cos x.$

Answer

Here $f (x) = \sin x \cos x$
$\therefore \;f{\text{}}(x) = \frac{d}{{dx}}(\sin x\cos x)$
$= \sin x\frac{d}{{dx}}(\cos x) + \cos x\frac{d}{{dx}}(\sin x)$
$= \sin x (- \sin x) + \cos x(\cos x) = \cos^2x - \sin^2x = \cos 2 x$

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