Question
Find the derivative of . $\text{x}^5(3-6\text{x}^{-9})$

Answer

Let $\text{f}(\text{x})=\text{x}^5(3-6\text{x}^{-9})$ By Leibnitz product rule, $\text{f}'\big(\text{x})=\text{x}^5\frac{\text{d}}{\text{dx}}\big(3-6\text{x}^{-9}\big)+\big(3-6\text{x}^{-9}\big)\frac{\text{d}}{\text{dx}}\big(\text{x}^5\big)$ $=\text{x}^5\big\{0-6(-9)\text{x}^{-9-1}\big\}+(3-6\text{x}^{-9})(5\text{x}^4)$ $=\text{x}^5(54\text{x}^{-10})+15\text{x}^4-30\text{x}^{-5}$ $=54\text{x}^{-5}+15\text{x}^4-30\text{x}^{-5}$ $=24\text{x}^{-5}+15\text{x}^4$ $=15\text{x}^4+\frac{24}{\text{x}^5}$

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