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Limits and Derivatives — MATHS STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceMATHSLimits and Derivatives1 Mark
Question
Find the derivative of x-4(3 - 4x-5)
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Answer

Here f(x) = x-4 (3 - 4x-5)
f'(x) = $\frac{d}{{dx}}$[x-4 (3 - 4x-5)]
$ = {x^{ - 4}}\frac{d}{{dx}}(3 - 4{x^{ - 5}}) + (3 - 4{x^{ - 5}})\frac{d}{{dx}}({x^{ - 4}})$
= x-4 (20x-6) + (3 - 4x-5) (-4x-5)
= 20x-10 - 12x-5 + 16x-10
= 36x-10 - 12x-5 $= \frac{{36}}{{{x^{10}}}} - \frac{{12}}{{{x^5}}}$

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