Question
Find the difference:
$2\frac{5}{9}-1\frac{7}{15}=\frac{23}{9}-\frac{22}{15}$
$2\frac{5}{9}-1\frac{7}{15}=\frac{23}{9}-\frac{22}{15}$
✓
Answer
$2\frac{5}{9}-1\frac{7}{15}=\frac{23}{9}-\frac{22}{15}$LCM of 9 and 15= 45
$\therefore\frac{23}{9}\frac{23\times5}{9\times5}=\frac{115}{45}$
$\frac{22}{15}=\frac{22\times3}{15\times3}=\frac{66}{45}$
$\therefore\frac{23}{9}-\frac{22}{15}=\frac{115}{45}-\frac{66}{45}$
$=\frac{115-66}{45}=\frac{49}{45}$
$\therefore\frac{23}{9}\frac{23\times5}{9\times5}=\frac{115}{45}$
$\frac{22}{15}=\frac{22\times3}{15\times3}=\frac{66}{45}$
$\therefore\frac{23}{9}-\frac{22}{15}=\frac{115}{45}-\frac{66}{45}$
$=\frac{115-66}{45}=\frac{49}{45}$
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