Question
Find the difference: $\frac{5}{6}-\frac{4}{9}$
✓
Answer
$\begin{array}{c|c}3&6,9\\\hline2&2,3\\\hline3&1,3\\\hline&1,1\end{array}$
$L.C.M$ of $6$ and $9 = (3 \times 2 \times 3) = 18$
Now, we have:
$\frac{5}{6}=\frac{5\times3}{6\times3}=\frac{15}{18}$
$\frac{4}{9}=\frac{4\times2}{9\times2}=\frac{8}{18}$
Therefore,
$\frac{5}{6}-\frac{4}{9}$
$=\frac{15}{18}-\frac{8}{18}$
$=\frac{(15-8)}{18}$
$=\frac{7}{18}$
$L.C.M$ of $6$ and $9 = (3 \times 2 \times 3) = 18$
Now, we have:
$\frac{5}{6}=\frac{5\times3}{6\times3}=\frac{15}{18}$
$\frac{4}{9}=\frac{4\times2}{9\times2}=\frac{8}{18}$
Therefore,
$\frac{5}{6}-\frac{4}{9}$
$=\frac{15}{18}-\frac{8}{18}$
$=\frac{(15-8)}{18}$
$=\frac{7}{18}$
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