Question
Find the difference: $\frac{5}{8}-\frac{7}{12}$

Answer

$\begin{array}{c|c}2&8,12\\\hline2&4,6\\\hline2&2,3\\\hline3&1,3\\\hline&1,1\end{array}$
$L.C.M$ of $2$ and $8 = (2 \times 2 \times 2 \times 3) = 24$
Now, we have:
$\frac{5}{8}=\frac{5\times3}{8\times3}=\frac{15}{24}$
$\frac{7}{12}=\frac{7\times2}{12\times2}=\frac{14}{24}$
Therefore,
$\frac{5}{8}-\frac{7}{12}$
$=\frac{15}{24}-\frac{14}{24}$
$=\frac{(15-14)}{4}$
$=\frac{1}{24}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Solve: $3(x + 2) - 2(x - 1) = 7​​​​$
Ratio of distance of the school from Mary’s home to the distance of the school from John’s home is $2 : 1.$
$a.\ $Who lives nearer to the school?
$b.\ $Complete the following table which shows some possible distances that Mary and John could live from the school.
Distance from Mary’s home to school $($in $km.)$ $10$   $4$    
Distance from John’s home to school $($in $km.)$ $5$ $4$   $3$ $1$
$c.\ $If the ratio of distance of Mary’s home to the distance of Kalam’s home from school is 1 : 2, then who lives nearer to the school?
 
Solve: $\frac{5}{7}+\frac{1}{3}$
Five square flower beds each of sides $1 m$ are dug on a piece of land $5 m$ long and $4 m$ wide. What is the area of the remaining part of land?
Complete the figure so that line l becomes the line of symmetry of the whole figure.
Determine if the $15, 45, 40, 120$ are in proportion.
What will happen to the area of a rectangle if its.
Length is doubled and breadth is halved.
The ratio of copper and zinc in an alloy is $9 : 7$. If the weight of zinc in the alloy is $9.8\ kg$, find the weight of copper in the alloy.
In each of the following numbers without doing actual division, determine Whether the first number is divisible by the second number:
(i) 3409122;6
(ii) 11309634; 8
(iii) 3501804; 4
A loading tempo can carry $482$ boxes of biscuits weighing $15\ kg$ each. Whereas a van can carry $518$ boxes each of the same weight. Find the total weight that can be carried by both the vehicles.