Question
Find the difference: $7-4\frac{2}{3}=\frac{7}{1}-\frac{14}{3}$
✓
Answer
$3\frac{3}{10}-1\frac{7}{15}=\frac{33}{10}-\frac{22}{15}$
$LCM$ of $1$ and $15 = 30$
$\therefore\frac{33}{10}\frac{33\times3}{10\times3}=\frac{99}{30}$
$\frac{22}{15}=\frac{22\times2}{15\times2}=\frac{44}{30}$
$=\frac{21-14}{3}=-\frac{7}{3}=2\frac{1}{3}$
$\therefore\frac{33}{10}-\frac{22}{15}=\frac{99}{30}-\frac{44}{30}$
$=\frac{99-44}{30}=\frac{55}{30}=1\frac{5}{6}$
$LCM$ of $1$ and $15 = 30$
$\therefore\frac{33}{10}\frac{33\times3}{10\times3}=\frac{99}{30}$
$\frac{22}{15}=\frac{22\times2}{15\times2}=\frac{44}{30}$
$=\frac{21-14}{3}=-\frac{7}{3}=2\frac{1}{3}$
$\therefore\frac{33}{10}-\frac{22}{15}=\frac{99}{30}-\frac{44}{30}$
$=\frac{99-44}{30}=\frac{55}{30}=1\frac{5}{6}$
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