Question
Find the difference: $7-4\frac{2}{3}=\frac{7}{1}-\frac{14}{3}$

Answer

$7-4\frac{2}{3}=\frac{7}{1}-\frac{14}{3}$
$LCM$ of $1$ and $3 = 3$
$\therefore\frac{7\times3}{1\times3}=\frac{21}{3}$
$\frac{7}{1}-\frac{14}{3}=\frac{21}{3}-\frac{14}{3}$
$=\frac{21-14}{3}=-\frac{7}{3}=2\frac{1}{3}$

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