Introduction to Three Dimensional Geometry — MATHS STD 11 Science — Question

1. $\sqrt{72}$

Solution:

Consider the problem,

Let the given points 

A(12, 3, 4) and B(4, 5, 2)

So, distance between A and B by distance formula.

$\text{AB}=\sqrt{(4-12)^2+(5-3)^2+(2-4)^2}=\sqrt{(-8)^2+2^2+(-2)^2}$

$=\sqrt{64+4+4}=\sqrt{72}$

So, distance between the points (12,3,4) and (4,5,2) is $\sqrt{72}\text{ Sq. units.}$