Question
Find the distance between the parallel lines 3x + 4y + 3 = 0 and 3x + 4y + 15 = 0.

Answer

Equations of the given parallel lines are 3x + 4y + 3 = 0 and 3x + 4y + 15 = 0 Here, $a=3, b=4, c_1=3$ and $c_2=15$

∴ Distance between the parallel lines

$\begin{aligned} & =\left|\frac{c_1-c_2}{\sqrt{a^2+b^2}}\right| \\ & =\left|\frac{3-15}{\sqrt{3^2+4^2}}\right|=\left|\frac{-12}{\sqrt{9+16}}\right|\end{aligned}$

$=\frac{12}{5}$ units

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