Question
Find the distance between the parallel lines $3x – 4y + 7 = 0$ and $3x – 4y + 5 = 0$

Answer

Here, $A = 3, B = –4, C_1 = 7$ and $C_2 = 5.$
Hence, the required distance is $d=\frac{|7-5|}{\sqrt{3^{2}+(-4)^{2}}}=\frac{2}{5}$

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