Question
Find the distance between the points $\Big(\frac{-8}{5},2\Big)$ and $\Big(\frac{2}{5},2\Big).$

Answer

The given points are $\text{A}\Big(\frac{-8}{5},2\Big)$ and $\text{B}\Big(\frac{2}{5},2\Big).$
Then, $\Big(\text{x}_1=\frac{-8}{5},\text{y}_1=2\Big)$ and $\Big(\text{x}_2=\frac{2}{5},\text{y}_2=2\Big)$
Therefore,
$\text{AB}=\sqrt{(\text{x}_2-\text{x}_1)^2+(\text{y}_2-\text{y}_1)^2}$
$=\sqrt{\Big\{\frac{2}{5}-\Big(\frac{-8}{5}\Big)\Big\}^2+(2-2)^2}$
$=\sqrt{(2)^2+(0)^2}=\sqrt{4+0}$
$=\sqrt{4}$
$=2\text{ units}$

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