CBSE BoardEnglish MediumSTD 10MathsCoordinate Geometry3 Marks
Question
Find the distance between the points:
P(a + b, a - b) and Q(a - b, a + b)
✓
Answer
The given points are P(a + b, a - b) and Q(a - b, a + b)
Then,$ [x_1 = (a + b), y_1 = (a - b)]$ and $[x_2 = (a - b)$, and $y_2 = (a + b)]$
$\therefore\text{PQ}=\sqrt{(\text{x}_2-\text{x}_1)^2+(\text{y}_2-\text{y}_1)^2}$
$=\sqrt{(\text{a}-\text{b}-\text{a}-\text{b})^2+(\text{a}+\text{b}-\text{a}+\text{b})^2}$
$=\sqrt{(-\text{2b})^2+(\text{2b})^2}$
$=\sqrt{\text{4b}^2+\text{4b}^2}$
$=\sqrt{\text{8b}^2}=2\sqrt{2\text{b}}\text{ units}.$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.