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Introduction to Three Dimensional Geometry — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsIntroduction to Three Dimensional Geometry2 Marks
Question
Find the distance from the origin to (6, 6, 7).
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Answer

Coordinates of the origin are (0, 0, 0)
$\therefore$ Distance from (0, 0, 0) to (6, 6, 7)
$=\sqrt{(6-0)^2+(6-0)^2+(7-0)^2}$
$=\sqrt{36+36+49}=\sqrt{121}$
= 11 units.
Hence, the required distance = 11 units.

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