Question
Find the domain of the following function:
$\text{f(x)}=\sin^{-1}\sqrt{\text{x}^2-1}$
$\text{f(x)}=\sin^{-1}\sqrt{\text{x}^2-1}$
⇒ x
2 $\in$ [1, 2] $\Rightarrow\text{x}\in\big[-\sqrt2,-1\big]\cup\big[1,\sqrt2\big]$ Hence, the domain is $\big[-\sqrt2,-1\big]\cup\big[1,\sqrt2\big]$Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\text{xy}=\text{a}^2$
$\vec{\text{a}}=2\hat {\text{i}}-\hat{\text{j}}+2\hat{\text{k}}$ and $\vec{\text{b}} =4\hat{\text{i}}+4\hat{\text{j}}-2\hat{\text{k}}$