Question
Find the edge of a cube whose surface area is $432 \mathrm{~m}^2$.
✓
Answer
Let, $\mathrm{a} \rightarrow$ Edge of the cube Surface area of the cube $=6 \mathrm{a}^2$ So, $6 \mathrm{a}^2=432 \mathrm{a}^2=\frac{432}{6}=72 \mathrm{a}=6 \sqrt{2} \mathrm{~m}$ Side of the cube is $6 \sqrt{2} \mathrm{~m}$.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Expand using suitable identity: $(x+2 y+4 z)^2$
→Can the experimental probability of an event be a negative number? If not, why?
Define complementary angles.
In the below figure. Name the following:
Four collinear points.
Four collinear points.
Write the following as an equation in two variables: $2x = -3$
→Identify constant, linear, quadratic, cubic and quadrtic polynomials from the following: $-p$
→Identify the polynomials in the following: $\text{f(x)}=2+\frac{3}{\text{x}}+4\text{x}$
→ Classify the following number as rational or irrational. give reasons to support your answer.
$\frac{22}{7}$
→$\frac{22}{7}$
Retionalise the denominator of each of the following: $\frac{3}{\sqrt5}$
→$E$ and $F$ are respectively the mid-points of equal sides $AB$ and $AC$ of $\triangle ABC $(see Fig.$)$. Show that $BF = CE$
→