Question
Find the edge of a cube whose surface area is $432m^2.$
✓
Answer
Let, $a \rightarrow$ Edge of the cube Surface area of the cube $=6 a^2$ So, $6 a^2=432 a^2=\frac{432}{6}$
$= 72$
$\text{a}=6\sqrt{2}\text{m}$
Side of the cube is $6\sqrt{2}\text{m}.$
$= 72$
$\text{a}=6\sqrt{2}\text{m}$
Side of the cube is $6\sqrt{2}\text{m}.$
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