Question
Find the equation of the hyperbola with:
$\text{Vertices }(0,\pm7),\text{ e}=\frac{4}{3}$

Answer

$\text{Vertices }(0,\pm7),\text{ e}=\frac{4}{3}$
$\therefore\ \text{b}=7,\text{ e}=\frac{4}{3}$
Now, $\text{a}^2=\text{b}^2(\text{e}^2-1)$
$=49\Big(\frac{16}{9}-1\Big)=\frac{343}{9}$
So, the equation of hyperbola is,
$\frac{\text{x}^2}{\text{a}^2}-\frac{\text{y}^2}{\text{b}^2}=-1$
$\Rightarrow\frac{\text{x}^2}{\frac{343}{9}}-\frac{\text{y}^2}{49}=-1$
$\Rightarrow9\text{x}^2-7\text{y}^2+343=0$

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