Question
Find the equation to the straight line which passes through the point (5, 6) and has intercepts on the axes Equal in magnitude and both positive,Equal in magnitude but opposite in sign.

Answer

Intercepts are equal positive⇒ a = b = k
The equation of straight line is
$\frac{\text{x}}{\text{a}}+\frac{\text{y}}{\text{b}}=1 \ ...(\text{i})$
Since this line passes through (5, 6) and a = b = k, we get:
$\frac{5}{\text{k}}+\frac{6}{\text{k}}=1$
$\text{k}=1$
$\therefore\frac{\text{x}}{11}+\frac{\text{y}}{11}=1$
$\Rightarrow\text{x}+\text{y}=11$
Intercepts are equal but opposite in sing
Let, a = k, b = -k
Putting in (i), we get,
$\frac{5}{\text{k}}+\frac{6}{-\text{k}}=1$
$\frac{5}{\text{k}}-\frac{6}{\text{k}}=1$
$\Rightarrow\text{k}=-1$
thus from (i)
$\text{x}-\text{y}=-1$

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