Question
Find the factors of $3m^2+ 9m + 6.$
✓
Answer
$ 3 m^2+9 m+6 $
$ =3\left(m^2+3 m+2\right) $
$ =3\left(m^2+m+2 m+2\right) $
$ =3[m(m+1)+2(m+1)] $
$ =3(m+1)(m+2) $
Therefore, the factors of $3m^2+ 9m + 6$ are $3, (m + 1)$ and $(m + 2).$
$ =3\left(m^2+3 m+2\right) $
$ =3\left(m^2+m+2 m+2\right) $
$ =3[m(m+1)+2(m+1)] $
$ =3(m+1)(m+2) $
Therefore, the factors of $3m^2+ 9m + 6$ are $3, (m + 1)$ and $(m + 2).$
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