Explanation:
Kirchhoff’s 2nd year is applied in a closed loop. Kirchhoff’s 2nd law supports the law of conservation of energy. This means that energy is neither created nor destroyed in the closed loop. Whatever energy enters the loop, same amount leaves the loop.
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Resistance of a voltameter is 2Ω, it is connected in series to a battery of 10 V through a resistance of 3Ω. In a certain time mass deposited on cathode is 1 gm. Now the voltameter and the 3Ω resistance are connected in parallel with the battery. Increase in the deposited mass on cathode in the same time will be
|
(a) 0 |
(b) 1.5 gm |
(c) 2.5 gm |
(d) 2 gm |
A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earth's magnetic field is 0.2 
, then the e.m.f. developed between the two ends of the conductor is
|
(a) 5mV |
(b) 5 |
(c) 50 mV |
(d) 50 μV |
A current carrying solenoid is approaching a conducting loop as shown in the figure. The direction of induced current as observed by an observer on the other side of the loop will be
|
(a) Anticlockwise |
(b) Clockwise |
(c) East |
(d) West |
A 100 W bulb B1, and two 60-W bulbs B2 and B3, are connected to a 250 V source, as shown in the figure. Now W1, W2 and W3 are the output powers of the bulbs B1, B2 and B3, respectively. Then
|
(a) |
(b) |
(c) 
|
(d) 
|
An oxide coated filament is useful in vacuum tubes because essentially
|
(a) It has high melting point |
|
(b) It can withstand high temperatures |
|
(c) It has good machanical strength |
|
(d) It can emit electrons at relatively lower temperatures |
Flint glass prism is joined by a crown glass prism to produce dispersion without deviation. The refractive indices of these for mean rays are 1.602 and 1.500 respectively. Angle of prism of flint prism is 10°, then the angle of prism for crown prism will be
|
(a) 12°2.4' |
(b) 12°4’ |
(c) 1.24° |
(d) 12° |
The value of internal resistance of an ideal cell is
|
(a) Zero |
(b) 0.5 Ω |
(c) 1 Ω |
(d) Infinity |
Focal length of a convex lens will be maximum for
|
(a) Blue light |
(b) Yellow light |
(c) Green light |
(d) Red light |
$\text{F = Mg}$
$\text{F}=\mu\text{Mg}$
$\text{Mg}\leq\text{F}\leq\text{Mg}\sqrt{1+\mu^2}$
$\text{Mg}\geq\text{F}\geq\text{Mg}\sqrt{1-\mu^2}.$
