Question
Find the following product: $10 a^2(0.1 a-0.5 b)$
✓
Answer
$=10 a^2 \times 0.1 a-10 a^2 \times 0.5 b$
$=10 \times 0.1 \times a^2 \times a-10 \times 0.5 \times a^2 \times b$
$=1 \times a^{(2+1)}-5 a^2 b$
$=a^3-5 a^2 b$
$=10 \times 0.1 \times a^2 \times a-10 \times 0.5 \times a^2 \times b$
$=1 \times a^{(2+1)}-5 a^2 b$
$=a^3-5 a^2 b$
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