Question
Find the following product:
$-17 x^2(3 x-4)$
$-17 x^2(3 x-4)$
✓
Answer
$=-17 x^2 \times 3 x-\left(-17 x^2 \times 4\right)$
$=-17 \times 3 \times x^2 \times x+17 \times 4 \times x^2$
$=-51 \times x^{(2+1)}+68 x^2$
$=-51 x^3+68 x^2$
$=-17 \times 3 \times x^2 \times x+17 \times 4 \times x^2$
$=-51 \times x^{(2+1)}+68 x^2$
$=-51 x^3+68 x^2$
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