Question
Find the following product:
$2 x^2\left(3 x-4 x^2\right)$

Answer

$=2 x^2 \times 3 x-2 x^2 \times 4 x^2$
$=2 \times 3 \times x^2 \times x-2 \times 4 \times x^2 \times x^2$
$=6 \times x^{(2+1)}-8 \times x^{(2+2)}$
$=6 x^3-8 x^4$

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