Question
Find the following product:
$(3 m-4 n)(2 m-3 n)$
$(3 m-4 n)(2 m-3 n)$
✓
Answer
$(3 m-4 n)(2 m-3 n)$
$=3 m(2 m-3 n)-4 n(2 m-3 n)$
$=(3 m \times 2 m-3 m \times 3 n)-(4 n \times 2 m-4 n \times 3 n)$
$=6 m^2-9 m n-8 n m+12 n^2$
$=6 m^2-17 m n+12 n^2$
$=3 m(2 m-3 n)-4 n(2 m-3 n)$
$=(3 m \times 2 m-3 m \times 3 n)-(4 n \times 2 m-4 n \times 3 n)$
$=6 m^2-9 m n-8 n m+12 n^2$
$=6 m^2-17 m n+12 n^2$
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