Question
Find the following product:
$\left(3 x^2+3 x-9\right)(3 x-9)$

Answer

By column method: $\ \ \ 3\text{x}^2+5\text{x}-9\\\underline{\ \ \ \ \ \ \ \ \times (3\text{x}-9)\ \ }\\ \ \ 9\text{x}^3\ +15\text{x}^2-27\text{x}\\\underline{\ \ \ \ \ \ \ \ \ -27\text{x}^2-45\text{x}+81\ \ }\\\ \ 9\text{x}^3\ -12\text{x}^2-72\text{x}+81$
$\therefore(3\text{x}^2+5\text{x}-9)(3\text{x}-9)$
$=9\text{x}^3-12\text{x}^2-72\text{x}+81$

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