Find the following product: -4 x^2 y (3 x^2-5 y )

Question

Find the following product:
$-4 x^2 y\left(3 x^2-5 y\right)$

✓

Answer

$=-4 x^2 y \times 3 x^2-\left(-4 x^2 y \times 5 y\right)$
$=-4 \times 3 \times x^2 \times x^2 \times y+4 \times 5 \times x^2 \times y \times y$
$=-12 \times x^{(2+2)} \times y+20 \times x^2 \times y^{(1+1)}$
$=-12 x^4 y+20 x^2 y^2$

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