Question
Find the following product:
$\left(9 x^2-x+15\right)(x 2-3)$
$\left(9 x^2-x+15\right)(x 2-3)$
✓
Answer
By column method: $9\text{x}^2-\text{x}+15\\\underline{\ \ \ \ \times (\text{x}^2-3)\ \ }\\9\text{x}^4-\text{x}^3+15\text{x}^2\\\underline{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -27\text{x}^2+3\text{x}-45}\\9\text{x}^4-\text{x}^3-12\text{x}^2+3\text{x}-45$
$\therefore (9\text{x}^2-\text{x}+15)(\text{x}^2-3)$ $=9\text{x}^4-\text{x}^3-12\text{x}^2+3\text{x}-45$
$\therefore (9\text{x}^2-\text{x}+15)(\text{x}^2-3)$ $=9\text{x}^4-\text{x}^3-12\text{x}^2+3\text{x}-45$
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