Question
Find the following product: $\Big(\frac{3}{4}\text{a}+\frac{2}{3}\text{b}\Big)(4\text{a}+3\text{b})$
✓
Answer
$\Big(\frac{3}{4}\text{a}+\frac{2}{3}\text{b}\Big)(4\text{a}+3\text{b})$ $=\frac{3}{4}\text{a}\times (4\text{a}+3\text{b})+\frac{2}{3}\text{b}\times (4\text{a}+3\text{b})$ $=\Big(\frac{3}{4}\text{a}\times 4\text{a}+\frac{3}{4}\text{a}\times3\text{b}\big)+\Big(\frac{2}{3}\text{b}\times 4\text{a}+\frac{2}{3}\text{b}\times 3\text{b}\Big)$ $=3\text{a}^2+\frac{9}{4}\text{ab}+\frac{8}{3}\text{ba}+2\text{b}^2$ $=3\text{a}^2+\frac{59}{12}\text{ab}+2\text{b}^2$
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