Question
Find the following product:
$\left(x^2-3 x+7\right)(2 x+3)$

Answer

By column method:
$x^2-3 x+7$
$\times(2 x+3)$
$2 x^3-6 x^2+14 x$
$\frac{3 x^2-9 x+21}{2 x^3-3 x^2+5 x+21}$
$\therefore\left(x^2-3 x+7\right)(2 x+3)$
$=2 x^3-3 x^2+5 x+21$

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