Question
Find the following product:
$\left(x^4+y^4\right)\left(x^2-y^2\right)$
$\left(x^4+y^4\right)\left(x^2-y^2\right)$
✓
Answer
$\left(x^4+y^4\right)\left(x^2-y^2\right)$
$=x^4\left(x^2-y^2\right)+y^4\left(x^2-y^2\right)$
$=\left(x^4 \times x^2-x^4 \times y^2\right)+\left(y^4 \times x^2-y^4 \times y^2\right)$
$=x^6-x^4 y^2+x^2 y^4-y^6$
$=x^4\left(x^2-y^2\right)+y^4\left(x^2-y^2\right)$
$=\left(x^4 \times x^2-x^4 \times y^2\right)+\left(y^4 \times x^2-y^4 \times y^2\right)$
$=x^6-x^4 y^2+x^2 y^4-y^6$
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